|V_ud|
Formula
$$|V_{ud}| = \cos\theta_{12}^{\rm CKM} \cdot \cos\theta_{13}^{\rm CKM}$$
Input theorems
This derivation uses the following theorems from the PT chain:
Derivation
|V_ud| — dominant diagonal
$|V_{ud}|$ is the largest CKM element (~0.974). It represents u ↔ d transition probability, dominating nuclear β decays.
In the standard parametrisation:
$$ |V_{ud}| = \cos\theta_{12}^{\rm CKM} \cdot \cos\theta_{13}^{\rm CKM}. $$
Computation
From the q_- branch (geometry / quarks), at $\mu^* = 15$: - $\sin^2\theta_{12}^{\rm CKM} = 0.0503$ (Cabibbo, see V_us) - $\sin^2\theta_{13}^{\rm CKM} = 1.45 \times 10^{-5}$
So: - $\cos\theta_{12} = \sqrt{1 - 0.0503} = 0.97456$ - $\cos\theta_{13} = 0.999993$
$$ |V_{ud}| = 0.97456 \cdot 0.999993 = 0.97418\ \rightarrow\ 0.97419\ \text{(NLO)}. $$
PT: 0.974 184 vs PDG: 0.97373 ± 0.00031. Gap: 0.047%.
Why almost 1?
$|V_{ud}|$ near 1 reflects near-perfect orthogonality of $p = 3$ vs $p = 5$ channels on q_-. The Wolfenstein hierarchy emerges naturally.
See also
- All 43 observables
- PT calculators — γ_p, sin²θ_p, α_EM live
- Full monograph
- Verification scripts