The Theory of Persistence
#41 · combinatorics

N_gen

PT value
3
PDG / CODATA
3
Error
exact

Formula

$$N_{\rm gen} = |\{p \text{ actif à } \mu^*\}| = |\{3,5,7\}| = 3$$

Input theorems

This derivation uses the following theorems from the PT chain:

Derivation

N_gen — number of fermion generations

$N_{\rm gen} = 3$: three fermion generations (e/μ/τ and u/c/t and d/s/b and $\nu_e$/$\nu_\mu$/$\nu_\tau$). In PT, a theorem:

$$ N_{\rm gen} = |\{p : \gamma_p(\mu^*) > 1/2\}| = |\{3, 5, 7\}| = 3. $$

Why exactly 3?

Same argument as $N_c = 3$ (ID 40): at $\mu^* = 15$, active primes are {3, 5, 7}. No others. T5 proves this by exhaustive rational scan.

The coincidence $N_{\rm gen} = N_c$ makes the Standard Model gauge-anomaly-free. Required for quantum consistency.

Epistemic status

Exact. Not a measurement, not a probabilistic prediction. Unconditional theorem: $|\{3, 5, 7\}| = 3$ by enumeration.

Indirect test

LEP measured the number of light neutrinos via $Z^0$ width: $N_\nu = 3.000 \pm 0.008$. If a 4th generation of light neutrinos ($m < m_Z/2$) were discovered, PT would fall. This is P12 in the list of falsifiable predictions.

See also essay [Why three fermion generations?](/en/essays/why-3-generations).


See also