#8 · quarks
m_d
PT value
4.656 MeV
PDG / CODATA
4.67 MeV
Error
0.290%
Formula
$$m_d = m_u \cdot \sin^2\theta_5(q_-) / \sin^2\theta_3(q_-) \cdot R_d$$
Input theorems
This derivation uses the following theorems from the PT chain:
Derivation
m_d — down quark
Down is the isospin partner of up. The ratio $m_d / m_u$ comes from isospin rotation on the geometric cascade:
$$ m_d = m_u \cdot \frac{\sin^2\theta_5(q_-)}{\sin^2\theta_3(q_-)} \cdot R_d, $$
with $R_d \approx 2.415$ (negative-isospin u → d correction, App. P §C8).
Computation
$$ m_d = 2.156 \cdot \frac{0.11181}{0.12489} \cdot 2.415 = 4.656\ \text{MeV}. $$
PT: 4.656 MeV vs PDG: 4.67 ± 0.07 MeV. Gap: 0.29%.
The ratio m_d / m_u
$m_d / m_u = 2.160$. Dimensionless, directly comparable: PDG gives ~2.16, PT 2.160. This ratio is a clear signature of the q_- geometric branch.
See also
- All 43 observables
- PT calculators — γ_p, sin²θ_p, α_EM live
- Full monograph
- Verification scripts