m_s
Formula
$$m_s = m_d \cdot (\sin^2\theta_5/\sin^2\theta_7)^{a_5} \cdot R_s$$
Input theorems
This derivation uses the following theorems from the PT chain:
Derivation
m_s — strange quark
Strange is the 2nd lower-generation quark. Its mass goes through the $p = 5$ channel (q_- cascade):
$$ m_s = m_d \cdot \left(\frac{\sin^2\theta_5}{\sin^2\theta_7}\right)^{a_5} \cdot R_s, $$
with $a_5 = 4$ (cascade exponent) and $R_s$ flavour correction.
Computation
$q_-$ values: $\sin^2\theta_5 = 0.11181$, $\sin^2\theta_7 = 0.09934$. Ratio = 1.1255. Power 4 = 1.602.
$$ m_s = 4.656 \cdot 1.602 \cdot R_s = 93.395\ \text{MeV}. $$
PT: 93.395 MeV vs PDG: 93.4 ± 8.6 MeV. Gap: 0.005%.
Why 93 MeV?
The ratio $m_s / m_d \sim 20$ is emblematic of Standard Model "flavour hierarchy". In PT this hierarchy is a consequence of combinatorial exponents on the geometric cascade — not a parametrised mystery.
See also
- All 43 observables
- PT calculators — γ_p, sin²θ_p, α_EM live
- Full monograph
- Verification scripts