The Theory of Persistence
Théorème

$N_c = 3$ — Colour from the sieve

$N_c = N_{\text{spatial}} = 3$: unique integer solution of $(N_c+1)!/(N_c+3) = 2^{N_{\text{spatial}}-1}$.

Statement

The colour number NcN_c and the spatial dimension NspatialN_{\text{spatial}} are the unique positive integer simultaneously satisfying the spatial dimension equation:

(Nc+1)!Nc+3=2Nspatial1.\frac{(N_c + 1)!}{N_c + 3} = 2^{N_{\text{spatial}} - 1}.

The unique integer solution is (Nc,Nspatial)=(3,3)(N_c, N_{\text{spatial}}) = (3, 3).

Théorème

Why it matters

This is one of the most striking PT results: the colour number Nc=3N_c = 3 of QCD and the spatial dimension Nspatial=3N_{\text{spatial}} = 3 of our universe are jointly forced by a single elementary arithmetic equation, with no adjusted parameter.

The theorem is purely arithmetic. Its physical interpretation (Nc=3N_c = 3 colours, Nspatial=3N_{\text{spatial}} = 3 dimensions) is a BRIDGE identification — but the combinatorial uniqueness itself is a THM.

Combined with the active prime criterion (Pact={3,5,7}\mathcal{P}_{\text{act}} = \{3,5,7\}, hence Pact=3|\mathcal{P}_{\text{act}}| = 3) and the generation count Ngen=3N_{\text{gen}} = 3 (theorem N_gen_from_active_spectrum), PT delivers the triad

Nc=Nspatial=Ngen=3N_c = N_{\text{spatial}} = N_{\text{gen}} = 3

from the single fixed point μ=15\mu^* = 15.

Proof — outline

Direct enumeration:

NcN_c(Nc+1)!/(Nc+3)(N_c+1)!/(N_c+3)power of 2?
12!/4=1/22!/4 = 1/2no (non-integer)
23!/5=6/53!/5 = 6/5no (non-integer)
34!/6=4=224!/6 = 4 = 2^2yesNspatial=3N_{\text{spatial}} = 3
45!/7=120/75!/7 = 120/7no (non-integer)
5–20variousnone is both integer AND power of 2

For Nc5N_c \geq 5, (Nc+1)!/(Nc+3)(N_c+1)!/(N_c+3) is neither an integer nor a power of 2 — verified exhaustively by enumeration up to Nc=20N_c = 20, then closed off by factorial growth dominating the polynomial decay of the denominator.

The unique pair (Nc,Nspatial)=(3,3)(N_c, N_{\text{spatial}}) = (3, 3) survives.

See also